A 250 mL buffer solution is prepared by using x g
of NH CI and V mL of 1 M NaOH solution.
At pH = 9.6, the concentration of NH ion in final
solution is 0.1 M. The value of x + V is (Kb of
NH,OH = 2 x 10-5)
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this is the numerical ?
i can't understand
akshithero100:
it is from chapter ionic equilibrium from class 11
A 250 mL buffer solution is prepared by using x g
of NH4CI and V mL of 1 M NaOH solution.
At pH = 9.6, the concentration of NH4+ ion in final
solution is 0.1 M. The value of x + V is (Kb of
NH4OH = 2 x 10-5)
of NH4CI and V mL of 1 M NaOH solution.
At pH = 9.6, the concentration of NH4+ ion in final
solution is 0.1 M. The value of x + V is (Kb of
NH4OH = 2 x 10-5)
ok i'll try
idk why 4 was missing from nh4
hmmmmmmmm
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