Question

A particle is moving at a velocity of 25m/s it comes to stop after 10s then calculate its retardation and displacement​

Answer 1

Answer:

U = 25 m/s

t = 10 s

V= 0 m/s

(1) by 1st equation of motion

V = u + at

0 = 25 + a(10)

-25/10 = a

-2.5 m/s^2

retardation = 2.5 m/s

(2) By 2nd equation of motion

S = ut + 1/2 at^2

S = 25(10) + 1/2( -2.5(10)^2)

S = 250 + 1/2 ( -250)

S = 250 - 125

S = 125m

Explanation:

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