A 250 watt electric bulb is lighted for 5 hours daily and 6 watt bulbs and lighted for 4.5 hours dqily calculate energy in February
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Power 1=250 watt
kilowatt hour=250/1000=0.25
Time 1=5 hours
28 days=5*28=140 hours
Power 2=6 watt
kilowatt hour=6/1000=0.006
Time 2=4.5 hours
28 days=4.5*28=126 hours
energy 1=p*t
energy 1=0.25*140=350 kilowatt hour
energy 2=p*t
energy 2=0.006*126=0.756
total energy in month of February=350+0.756
=350.756 kilowatt hour
kilowatt hour=250/1000=0.25
Time 1=5 hours
28 days=5*28=140 hours
Power 2=6 watt
kilowatt hour=6/1000=0.006
Time 2=4.5 hours
28 days=4.5*28=126 hours
energy 1=p*t
energy 1=0.25*140=350 kilowatt hour
energy 2=p*t
energy 2=0.006*126=0.756
total energy in month of February=350+0.756
=350.756 kilowatt hour
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