A 2500cm cube of hydrogen at S.T.P is subjected to 2.5 times increase in pressure. What volume will hydrogen now occupy?temperature remaining constant
Answers
Answered by
4
Given, V1 =2500 cm3
P1 =760mm [At S.T.P]
It is said that Hydrogen is subjected to 2.5 times increase in pressure.
Thus final pressure , P2 of the gas is = 2.5 x P1
= 2.5 x 760
P2 = 1900 mm
We have to find out V2 [final volume] which the gas occupies
From Boyle's Law, At constant temperature
P1V1 = P2V2
Thus , V2 = P1V1P2
V2 = 2500×7601900
V2 = 1000cm3
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
P1 =760mm [At S.T.P]
It is said that Hydrogen is subjected to 2.5 times increase in pressure.
Thus final pressure , P2 of the gas is = 2.5 x P1
= 2.5 x 760
P2 = 1900 mm
We have to find out V2 [final volume] which the gas occupies
From Boyle's Law, At constant temperature
P1V1 = P2V2
Thus , V2 = P1V1P2
V2 = 2500×7601900
V2 = 1000cm3
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Answered by
7
Answer:5000/7 cucm
Explanation:
V1=2500, P1=760mm
V2=?, P2=2 and 1/2 times increase in P1
P2 = 760 + ( (5/2) *760)
=760 + (5*380)
=760 + 1900
P2 =2660 mm
P1V1 = P2V2
V2 = P1V1 / P2
V2 = (2500 * 760) / 2600
= (2500 * 2) / 7
V2 = 5000/7 cucm
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