Question

A 25kg box is pulled at a constant speed by a horizontal force on a horizontal floor .The coefficient of sliding friction between the box and the floor is 0.20.How much work is done in pulling the box through 20m?

Answer 1

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➧ Work = force × displacement cosθ

➧ Force of friction =
Coefficient of friction × normal reaction
➾ 0.2 × mg

➾ 0.2 × 25 × 10
➾ 50 N

➧ Force × displacement

➾ 50N × 20 m
➾ 1000 J ...✔

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Thanks...✊

Answer 2

Answer:

1000 joules of work is done in pulling the given box.

Explanation:

• Work done is calculated by multiplying the force and displacement.
• The ratio of the frictional force resisting the movement of the two surfaces which are in contact with the normal force, is known as the coefficient of friction.
• Since there is no acceleration,

                                   Force = frictional force

And we know that,

                            work done = force × displacement

Given,

       mass = 25 kg

       The coefficient of friction (μ) = 0.20

       ∴  Force = mgμ

                     = 25 × 10 × 0.2

                     = 50 newton

Work done = Force × displacement

                   = 50 × 20 joules

                   = 1000 joules

So, the work done in pulling a box of 25 kg is 1000 joules.