Question

a 25m long ladder is placed against a vertical wall such that the foot of the ladder is 7m from the feet of wall. if the top of the ladder slides down by 4m by how much distance will the foot of the ladder slide?

Answer 1

Pls see attachment which I am attaching to the answer it is explained there otherwise answer is by 8 m

Answer 2

Answer:

The foot of ladder slides from 7m to 15 m from the wall and the magnitude if slide is 8m.

Step-by-step explanation:

Given : 25m long ladder is placed against a vertical wall such that the foot of the ladder is 7m from the feet of wall. if the top of the ladder slides down by 4m.

To find : How much distance will the foot of the ladder slide?

Solution :

According to question,

It form a right angled triangle,

Where, Base=7

Hypotenuse =25

Applying Pythagoras theorem,

So, vertical height will be

$P=\sqrt{(25^2-7^2)}\\P=\sqrt{625-49}\\P=\sqrt{576}\\P=24$

Now vertical height reduces to 24-4 =20 as the ladder slips.

Hypotenuse is same  25 , P=20

New base is

$B=\sqrt{(25^2-20^2)}\\B=\sqrt{625-400}\\B=\sqrt{225}\\B=15$

So, the foot of ladder slides from 7m to 15 m from the wall and the magnitude if slide is 8m.