A 25m long ladders placed against a wall to reach a window 7m high. Find the distance of the of the ladder from the wall
Answers
Answer:
A 25 m long ladder is placed against the wall to reach a Window 7 M I find the distance of the ladder from the wall find it in NCERT solution
Answer:
The foot of ladder slides from 7m to 15 m from the wall and the magnitude if slide is 8m.
Step-by-step explanation:
Given : 25m long ladder is placed against a vertical wall such that the foot of the ladder is 7m from the feet of wall. if the top of the ladder slides down by 4m.
To find : How much distance will the foot of the ladder slide?
Solution :
According to question,
It form a right angled triangle,
Where, Base=7
Hypotenuse =25
Applying Pythagoras theorem,
So, vertical height will be
\begin{gathered}P=\sqrt{(25^2-7^2)}\\P=\sqrt{625-49}\\P=\sqrt{576}\\P=24\end{gathered}
P=
(25
2
−7
2
)
P=
625−49
P=
576
P=24
Now vertical height reduces to 24-4 =20 as the ladder slips.
Hypotenuse is same 25 , P=20
New base is
\begin{gathered}B=\sqrt{(25^2-20^2)}\\B=\sqrt{625-400}\\B=\sqrt{225}\\B=15\end{gathered}
B=
(25
2
−20
2
)
B=
625−400
B=
225
B=15
So, the foot of ladder slides from 7m to 15 m from the wall and the magnitude if slide is 8m