Question

a 26 feet ladder leans against a wall at height of 24 feet from the ground how far the base of the ladder form the wall
please answer step by step explanation​

Answer 1

Answer :

10 feet

Explanation :

In the figure, the ladder is the hypotenuse, the wall is perpendicular and we need to find the lenght of the base.

By Pythagoras theorem,

→ h² = p² + b²

Where,

• h(hypotenuse) = 26 feet.
• p(perpendicular wall) = 24 feet.
• base = b (assuming)

So,

→ 26² = 24² + b²

→ 676 = 576 + b²

→ 676 - 576 = b²

→ 100 = b²

→ √100 = b

→ 10 = b

∴ The base lenght is 10 feet.

Answer 2

Given:-

• length of ladder is 26 feet.
• length of wall is 24 feet.

To find:-

• base of ladder form the wall?

Solution:-

According to Pythagoras theorem:-

$\dag{ \underline{ \boxed{\rm { \pink{ {h}^{2} = {p}^{2} + {b}^{2}}}}}}$

Where,

• h = 26 feet
• p = 24 feet
• b = (to find)

So,

$\longrightarrow{26}^{2} = {24}^{2} + {b}^{2} \\ \\\longrightarrow 676 = 576 + {b}^{2} \\ \\ \longrightarrow{b}^{2} = 676 - 576 \\ \\ \longrightarrow{b}^{2} = 100 \\ \\ \longrightarrow b = \sqrt{100} \\ \\\longrightarrow \dag { \boxed{ \underline{ \blue{b = 10 \: feet}}}}$

Hence, the measure of base is 10 feet.