Question

A 26m ladder is placed against the wall in such a way that the foot of the ladder is 10 cm away from the wall. How up on the wall is the upper end of the ladder?

Answer 1

hey there here is your answer...

I think the distance between wall and inclined ladder is 10m. not 10 cm.
and I have drawn fig. according to it.

from fig.

it is a right angled triangle

wall length from the ground to the inclined ladder spot
using Pythagoras thoerem

${26}^{2} = {10}^{2} + {x}^{2} \\ {x }^{2} = 676 - 100 \\ {x}^{2} = 576 \\ x = 24$
hope it helps..

Answer 2

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Here is the solution:

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*Assuming that the 10cm is meant to be 10m

Find the height of the wall:

a² + b² = c²

a² + 10² = 26²

a² = 26² - 10²

a² =576

a ≈ 24 m

Answer: The height of the wall from the ground to the top of the ladder is 24 m