(a+2b)/(3a-b)= (-b+3c)/(4b-c)=(2a+2b+1)/(4c+1) find a/b
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ab=23⟹a+bb=2+33using componendo
⟹a+bb=53(1)
bc=45⟹b+cc=4+55using componendo
⟹b+cc=95(2)
dividing (1) by (2)
c(a+b)b(b+c)=2527
⟹a+bb+c×cb=2527
⟹a+bb+c=2527×bc
⟹a+bb+c=2527×45=2027
I hope you are understand My solution
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