Question

(a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)​

Answer 1

Answer:

➙ (a-2b+5c)(a-b) -(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)

⇒(a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(a+b)(2c-3a-5b)

⇒[(a-b)(a-2b+5c)]-[(2a+3c)(a-b-c)]+[(6a+b)(2c-3a-5b)]

⇒[a(a-2b+5c)-b(a-2b+5c)]-[2a(a-b-c)+3c(a-b-c)]+[6a(2c-3a-5b)+b(2c-3a-5b)]

⇒(a²-2ad+5ac-ab+2b²-5bc)-(2a²-2ab-2ac+3ac-3bc-3c²)+(12ac-18a²-30ab+2bc-3ab-5b²)

⇒(a²+2b²-3ab+5ac-5bc)-(2a²-3c²-2ab+ac-3bc)+(-18a²-5b²+12ac-33ab+2bc)

⇒19a²-3b²-3c²-38ab+18ac-6bc

∴(a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)

⇒-19a²-3b²-3c²-38ab+18ac-6bc

Hence,

(a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)

⇒19ca-37ab-19a²

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Answer 2

Step-by-step explanation:

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