Question

A 2cm object is placed perpendicular to the principal axis of convex lens of focal length 10cm , The distance of the object from the lens is 15cm , find the nature and position of the image​

Answer 1

Answer:

Hey dear,

Height of object(h)= +2

Focal length(f)= +10

Object distance(u)= -15

Image distance(v)=?

Height of image (h')=?

since,1/f=1/v-1/u

1/v=1/u+1/f

1/v= -1/15+1/10

= -2+3/30

=1/30

V=+30

M=h'/h=v/u

m=+30/-15

M=-2

Explanation:

Hope this help you

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