a 2cm tall object is placed 40cm from a convex lens of focal length 15cm find the position size and magnification of the image also state the nature of the image formed
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anjali5371:
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height = 2 cm
object distance(u)= -40cm
focal length=+15cm(convex lens)
by lens formula:_
1/v-1/u=1/f
1/v-1/-40=1/15
1/v=1/15+1/-401/v=8-3/120
1/v=5/120
therefore v=24cm
size=v/u=h2/h1
24/-40=h2/2
= -1.2cm
the image is virtual and erect !
hope it helps
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