A 2cm tall object is placed perpendicular to the principal axis of the convex lens of focal length 10cm. the distance of objects from the lens is 15cm. find the nature, position and size of the image. Also find its magnification..
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Answered by
7
we have,
u=15cm
f=10cm
v=?
1/f=1/v+1/u
1/v=1/f-1/u
v=30cm
use formula m=v/u
=30/15=2
image is double it's size as magnification is 2
image is inverted as one ray passes through focus(f1) and second ray passes through f2
u=15cm
f=10cm
v=?
1/f=1/v+1/u
1/v=1/f-1/u
v=30cm
use formula m=v/u
=30/15=2
image is double it's size as magnification is 2
image is inverted as one ray passes through focus(f1) and second ray passes through f2
Answered by
10
I hope it helpful to u
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