Math, asked by prabhakarreddy6891, 1 year ago

A 2digit no. Such that the product of the digit is 8 ,when 18 is added to the number ,then the digits are reversed. The no. Is

Answers

Answered by Anonymous
9

Question:



A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:





Answer:



Required Number = 24




Method of Solution:





Let to be 10's unit Digit Number 'x'



Let to be 1's unit Digit Number 'y'

Also, Original Number = 10x+y

Required Number = 10y+x

Now, According to the Question's Statement

Let the two digit number is 10x+y

Product of the digits xy=8

Again, Following the Questions Statement!

10x+y+18=10y+x

10x -x +y-10y = -18

9x-9y = -18

•°• x-y = -2 ------(1)

Again, xy = 8 ----(2)

On Solving the Equations (1) and (2) , We get!

Value of x = 2

Value of Y = 4

Substitute the Given value in Equation!

Required Number = 10x+y

Required Number = 10(2) + 4

•°• Number = 24


Answered by Awesome98
2


10x+y+18=10y+x

10x -x +y-10y = -18

9x-9y = -18

l x-y = -2 --(1)

xy = 8 ----(2)


On Solving both Equations (1) and (2) , We get!


x = 2

Y = 4






Required Number = 10(2) + 4

Required Number = 24



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