Question

A 2g ball of glass is released from the edge of a hemispherical cup whose radius is 20 cm. how mucj work is done

Answer 1

As the Gravitational force is CONSERVATIVE in nature hence Work done by it depends only on initial and find position._____________We will consider only VERTICAL direction only. Because we have to take that displacement which is along the Gravitational force .

______________Initially the ball at the top of the hemispherical cup whose radius is 20cm.it means that initially the ball at height of 20cm from the ground . And finally it comes to ground . => Displacement of ball = 20 cm = 0.20 m ._____________Given that mass (m) of ball is 2g = 0.002Kg.So Gravitational Force acting on it = mg = 0.002×10 = 0.02N.______________Finally WORK DONE = force ×displacement ;= 0.02×0.20 = 0.004 J _______________hope it helps !

Answer 2

Hey

3.92 mj

i hope its help you
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