Math, asked by rickpegup87cxs, 1 year ago

If x:y=2:7 and y:z=9:11,find x:y:z


rickpegup87cxs: please hlp

Answers

Answered by ak260339p1m1fd
139
first find the l.c.m of y =7,9 so to common y in both the ratios , we got 63 then
x/y= 2/7×9/9=18/63
y/z=9/11×7/7=63/77
then here we can take one y as a common
so the ans.
x:y:z= 18:63:77
Answered by SerenaBochenek
76

Answer:

x:y:z=18:63:77

Step-by-step explanation:

Given that if x:y=2:7 and y:z=9:11

we have to find x:y:z

As, x:y=2:7

\frac{x}{y}=\frac{2}{7}

y=\frac{7}{2}x

and y:z=9:11 i.e

\frac{y}{z}=\frac{9}{11}

z=\frac{11}{9}y=\frac{11}{9}\times\frac{7}{2}x=\frac{77}{18}x

Therefore,

x:y:z=x:\frac{7}{2}x:\frac{77}{18}x

x:y:z=18:63:77

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