A 2gm bullet is fired from a 2kg rifle with a velocity of 200m/sec North wards, the recoil velocity of the rifle is
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Explanation:
Given:-
A 2gm bullet is fired from a 2kg rifle with a velocity of 200m/sec North wards.
To find:-
Find the recoil velocity of the rifle ?
Solution:-
Mass of the bullet = 2 gm
Mass of the rifle = 2kg
Velocity = 200 m/sec
We know that
The external force = 0
Since for The firle and bullet system
The momentum Conservation =
Initial momentum = Final mimentum
We have m = 2 gm = 2/1000 kg = 2×10^-3 kg
and u = 200 m/sec and M = 2kg
Mv +mu = 0
=>2v + 2×10^-3×200 = 0
=>2v +(2/1000)×200 = 0
=>2v +(400/1000)=0
=>2v + (4/10)=0
=>2v + 0.4 = 0
=>2v = -0.4
=>v = -0.4/2
=>v = -0.2 or -2×10^-1 m/sec
v = - 0.2 m/sec or -2×10^-1 m /sec
Here negative sign represents the velocity of rifle is opposite to that of the bullet.
Answer:-
The recoil velocity if the rifle is -0.2 m/s or -2×10^-1 m/s
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