Question

A 2kg body is allowed to roll down an inclined plane 4m long with angle of inclination 30°.calculate the work done (take g as 10ms–2)

Answer 1

$\underline{ \boxed{ \mathfrak{ \huge{ \pink{Answer}}}}} \\ \\ \star \: \boxed{\rm{Given}} \\ \\ \implies \rm \: mass \: of \: body = 2kg \\ \\ \implies \rm \: distance \: covered \: by \: body = 4m \\ \\ \implies \rm \: angle \: of \: inclination = 30 \degree \\ \\ \implies \rm \: g = 10 \frac{m}{ {s}^{2} } \\ \\ \star \: \boxed{\rm{To \: Find}} \\ \\ \implies \rm \: net \: work \: done \: by \: body \\ \\ \star \: \boxed{\rm{Formula}} \\ \\ \implies \rm \: net \: work \: is \: given \: as \\ \\ \: \: \: \: \: \: \: \: \: \: \: \dagger \: \: \underline{\boxed{ \rm{ \bold{ \red{W{ \tiny{ net}} = F{ \tiny{net}} \times d}}}}} \: \: \dagger \\ \\ \implies \rm \: in \: this \: condition \: net \: force \\ \rm \: on \: the \: body \: is \: \underline{\blue{mgsin30 \degree}} \\ \\ \star \: \boxed{\rm{Diagram}} \\ \\ \implies \rm \: see \: the \: attached \: image \: for \: better \\ \rm understanding \\ \\ \star \: \boxed{\rm{Calculation}} \\ \\ \implies \rm \: W = mgsin30 \degree \times d \\ \\ \implies \rm \: w = 2 \times 10 \times \frac{1}{2} \times 4 \\ \\ \implies \: \underline{\boxed{ \red{ \mathfrak{W = 40 \: J}}}}$

Answer 2

prefer attached image for answer....