Question

A,2kg body is sliding up an inclined plane of inclination 30degree. Find the work done by the force of gravity in moving the body through 1 metre​

Answer 1

Given :-

Mass of the body = 2 kg

Body inclined = 30°

Distance the body moving = 1 m

To Find :-

The work done by the force of gravity.

Solution :-

We know that,

• w = Work done
• g = Gravity
• m = Mass
• d = Distance

Using the formula,

$\underline{\boxed{\sf Work \ done=Fdcos(90- \theta)}}$

Angle between force and direction of displacement = 90 - θ

Substituting their values,

⇒ mg × d sinθ

⇒ mg × d sin30°

⇒ 2 × 10 × 1 × 1/2

⇒ 20/2

⇒ 10 J

Therefore, the work done by the force of gravity in the moving body is 10 J.

Answer 2

To Find :-

The work done by the force of gravity.

Solution :-

We know that,

w = Work done

g = Gravity

m = Mass

d = DistanceAngle between force and direction of displacement = 90 - θ

Substituting their values,

⇒ mg × d sinθ

⇒ mg × d sin30°

⇒ 2 × 10 × 1 × 1/2

⇒ 20/2

⇒ 10 J

Therefore, the work done by the force of gravity in the moving body is 10 J