a 2kg mass with speed of 0.5m/s collides elastically head on with a1.5kg mass moving with speed 0.3m/s towards the first mass. what is the speed of the second mass after collision
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the particles have collided elastically, therefore the coefficient of restitution will be 1
m1u1+m2u2 = m1v1+m1v1
(2)(0.5)+(1.5)(-0.3) = (2)(-0.5)+(1.5)(v2l
1-4.5 = -1+(v2)1.5
(1.5)(v2)-1 = -3.5
1.5v2 = -3.5+1
1.5v2 = -2.5
v2 = -5/3
m1u1+m2u2 = m1v1+m1v1
(2)(0.5)+(1.5)(-0.3) = (2)(-0.5)+(1.5)(v2l
1-4.5 = -1+(v2)1.5
(1.5)(v2)-1 = -3.5
1.5v2 = -3.5+1
1.5v2 = -2.5
v2 = -5/3
Anonymous9999:
How is |V1| = 0.5
it will move with the same speed in opposite direction
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