Question

A 2muF capacitor is connected to a 10 V battery. What is the electrostatic energy stored in the capacitor?

Answer 1

Answer:

energy stored = 1/2 CV²

Explanation:

E = 1/2 × 2 × 10^-6 ×10 ×10

E= 10^-4 J

hope it helps

Answer 2

Answer:

2×10^-6

Explanation:

Given,

C=2muF=2×10^-6

V=10v

Q=required

From,

Q=CV

Q=2×10^-6×10

Q=20×10^-6C

Q=2×10^-6

Hope it's helpful

Mark me as brainliest PLYYZZZZ