Question

Three capacitors each of capacitor 2muF are connected in series. Find resultance capacity in farad.

Answer 1

Answer:

0.67 × 10^-6 Farad

Explanation:

Capacitors in series are like resistors in parallel.

Hence, to find resultant capacity, since value of all 3 capacitors is 2 micro farad,

resultant capacity = value of capacitor ÷ number of capacitors

=2÷3 = 0.67microfarad= 0.67×10^-6 farad

Answer 2

Answer:

$\mathtt \pink{\frac { 1 } { C } = \frac { 1 } { C _ { 1} } + \frac { 1 } { C _ { 2 } } + \frac { 1 } { C _ { 3 } } + \cdots + \frac { 1 } { C _ { n } }}$