Math, asked by vasudevvs2003, 4 months ago

a=2x^-1/2x^-2,b=2^-x/2^x-11 and a-b=0 find the value of x

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Answers

Answered by SudeepDas0926
1

Answer:

ANS: 2x - 2^(-2x+11)

Step-by-step explanation:

For a

(2x)^-1/(2x)^-2 = 2x(If we reciprocate the expression then we get the result by cancellation of the power due to same base)

For b

2^(-x)/2^(x-11)= 2^(-2x+11) by the method stated above

a-b = 2x - 2^(-2x+11)

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