Math, asked by tanishka36, 1 year ago

a^2x^2+(ax^2+1)x+a factorise by grouping method

Answers

Answered by FireworldPrachi
141
a^2*x^2+(ax^2+1)x+a
= a^2*x^2+ax^3+x+a
= a^2*x^2+a+ax^3+x
= a(ax^2 + 1) + x(ax^2 + x)
= (a+x)(ax^2+1)



Hope this helps u
Answered by JackelineCasarez
18

(a+x) (ax^2+1)

Step-by-step explanation:

To factorize,

a^2*x^2 + (ax^2+1)x + a

By multiplying the terms,

= a^2*x^2 + ax^3 + x + a

By taking the common terms out,

= a^2*x^2 + a + ax^3 + x

So we get,

= a(ax^2 + 1) + x(ax^2 + x)

= (a+x) (ax^2+1)

Learn more: factorize

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