a^2x^2+(ax^2+1)x+a factorise by grouping method
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Answered by
141
a^2*x^2+(ax^2+1)x+a
= a^2*x^2+ax^3+x+a
= a^2*x^2+a+ax^3+x
= a(ax^2 + 1) + x(ax^2 + x)
= (a+x)(ax^2+1)
Hope this helps u
= a^2*x^2+ax^3+x+a
= a^2*x^2+a+ax^3+x
= a(ax^2 + 1) + x(ax^2 + x)
= (a+x)(ax^2+1)
Hope this helps u
Answered by
18
(a+x) (ax^2+1)
Step-by-step explanation:
To factorize,
a^2*x^2 + (ax^2+1)x + a
By multiplying the terms,
= a^2*x^2 + ax^3 + x + a
By taking the common terms out,
= a^2*x^2 + a + ax^3 + x
So we get,
= a(ax^2 + 1) + x(ax^2 + x)
= (a+x) (ax^2+1)
Learn more: factorize
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