Find the value (s) of k for which the pair of linear equations kx+y=k² and x+ky=1 have infinity many solutions
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deepak843410008:
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In kx+y-k²=0 and x+ky-1=0,
a1 = k; b1 = 1; c1 = - k²; a2 = 1; b2 = k & c2 = -1
For infinity many solutions
a1/a2 = b1/b2 = c1/c2
∴ a1/a2 = c1/c2
or, k/1 = -k²/-1
or, k = k²
∴ k = 1
HOPE IT HELPS....... :)
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