Math, asked by mindmindcraft20, 7 months ago

A=√(2x+3y) + √(√2x-3y)/
√(2x+3y) - (2x - 3y)
Find the value of 3ya^2 -4ax+3y​

Answers

Answered by Alishasheikh1108
2

Answer:

Step-by-step explanation:

A=√(2x+3y) + √(√2x-3y)/

√(2x+3y) - (2x - 3y)

Find the value of 3ya^2 -4ax+3y​ HOPE IT HELPS

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