a=3+2√2 then find the value of a²+1/a²
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asquare= (3+2✓2)(3+2√2)= 9+6√2+6✓2+4x2= 9+12√2+8= 17+12√2.............,........................
17+12√2+1/17+12√2=. 289+288+24x17√2/17+12√2
17+12√2+1/17+12√2=. 289+288+24x17√2/17+12√2
Answered by
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a² = 9 + 8 + 12√2
1/a² = 1/(17+ 12√2)
Adding both,
17+12√2 + 1/(17+12√2)
= (17+12√2)² + 1/(1)
= 577+ 408√2
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