(a-3)^2+(b-4)^2+(c-9)^2=0
Answers
Answered by
1
Answer is - a=3,b=4,c=9
As we know that if the sum of square of real numbers equals to zero then the real numbers are individually becomes zero.
So, here we can say -
a-3=0 therefore a=3
b-4=0 therefore b=4
c-9=0 therefore c=9
Hope it helped you!
As we know that if the sum of square of real numbers equals to zero then the real numbers are individually becomes zero.
So, here we can say -
a-3=0 therefore a=3
b-4=0 therefore b=4
c-9=0 therefore c=9
Hope it helped you!
priyanshsssist:
final answer pls
It's the final answer !
wrong
How ?
Then tell me what's the real answer?
Answered by
1
Answer:
a=3,b=4,c=9
Step-by-step explanation:
a-3=0
a=3
b-4=0
b=4
c-9=0
c=9
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