a^3+3a^2+9a=1 then a^3+3/a=?
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Given that
a³+3a²+9a = 1 ...(1)
a(a²+3a+9) = 1
So 1/a = a²+3a+9
⇒ 3/a = 3a²+9a+27 ...(2)
Hence value of
a³+3/a = a³+3a²+9a+27 [ using (1) ]
a³+3/a = 1+27 [ using (2) ]
a³+3/a = 28
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