Question

a^3+3a^2b+3ab^2+b^3-8
It's a question of RS Aggarwal class 9
Ex:-3F Q.No.:-25

Answer 1

$a^3+3a^2b+3ab^2+b^3-8$

We can write the given question as,

$a^3+3a^2b+3ab^2+b^3-8=(a + b)^3 - 2^3$

According to the equation,

$a^3 + b^3=(a - b)(a^2 + ab + b^2)$

So we get,

$(a + b)^3 - 2^3$

$=((a + b) - 2)((a + b)^2 + (a + b)2 + 2^2)$

$=(a + b - 2)((a + b)^2 + 2(a + b) + 4)$