Question

a^(3)-8b^(3)-64c^(3)-24abc

Answer 1

we can write....

a^(3) + (-8b^(3)+(-64c^(3)-24abc

use the identity

( a+b+c) ( a^2 + b^2 +c^2 -ab- bc- ca)

( a -2b - 4c) ( a^2 + 4b^2 + 16c^2 + 2ab - 8bc + 4ac).......

Answer 2

Answer:

(a-2b-4c)[a^2+4b^2+16c^2+2ab−8bc+4ac].

Step-by-step explanation:

We know that -

x^3+y^3+z^3 - 3xyz =(x+by+z)[x^2+y^2+z^2−xy−yz−xz]

If we see, in the expression, x = a and y = -2b and z = -4c

Therefore, if we substitute the values into the identity, we get -

a^3 - 8b^3 - 64c^3 -24abc =(a-2b-4c)[a^2+4b^2+16c^2+2ab−8bc+4ac].

Have a nice day !!!

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