Question

a^3+b^3+3ab=1 find a and b

Answer 1

Answer:

We know that (a−b)3=a3−b3−3ab(a−b)

Given that

a−b=1

Cubing on both sides, we get

⇒(a−b)3=a3−b3−3ab(a−b)

Substituting the value of a−b we get,

⇒(1)3=a3−b3−3ab(1)

Therefore, ⇒a3−b3−3ab=1

Answer 2

Answer:

(a–b)=a^3–b^3–3ab(a–b)

Step-by-step explanation:

(a–b)=a^3–b^3–3ab(a–b)

so,

a–b=1

(1)=a^3–b^3–3ab(1)

Hence,

a^3–b^3+3ab=1