Question

a^3+b^3-8+6ab solve in factor​

Answer 1

Step-by-step explanation:

${a}^{3} + {b}^{3} - 8 + 6ab \\ (a \times a \times a ) + (b \times b \times b) - (2 \times 4) + (2 \times 3 \times a \times b) \\ (a + b) \times( 4 - 3ab ) - 2(4 - 3ab) \\ (a + b - 2)(4 - 3ab) = 0$