Question

a^3+b^3-8c^3+6abc find by using suitable identity ​

Answer 1

Answer:

use identity: a³+b³+c³-3abc= (a+b+c)(a²+b²+c²-ab-bc-ca)

Answer 2

Answer:

(a−b+2c) × (a^2+b^2+4c^2+ab+2bc−2ca)

Step-by-step explanation:

Using identity,

x^3+y^3+z^3−3xyz = (x+y+z)(x^2+y^2+z^2−xy−yz−zx)

We get,

a^3−b^3+8c^3−6abc = (a−b+2c) × (a^2+b^2+4c^2+ab+2bc−2ca)