a/3=b\4=c/7,the a+b+c/c=
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5
a3=b4=c7a3=b4=c7
So,
=>a3=c7=>a3=c7
=>ac=37=>ac=37 ..... (1)
Also,
=>b4=c7=>b4=c7
=> bc=47bc=47
Now, a+b+cc=ac+bc+cca+b+cc=ac+bc+cc
=> ac+bc+1ac+bc+1
From (1) and (2)
=>37+47+1=3+4+77=>37+47+1=3+4+77
=> 147=2
sanyam80:
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