Question

A 3 cm object is placed Infront of a concave mirror and image formed is 9cm in height.what is the magnification of this object

Answer 1

Answer:

Explanation:

Using spherical mirror formula: (1/f)= (1/u) + (1/v), where, f=- 18 cm is focal length of the mirror, u=- 9 cm is object distance and v=? is image distance. We have used Cartesian sign convention .

Therefore , (-1/18) -(1/-9)= (1/v)=(1/18). Then, v=18cm.

The image is erect, virtual and positioned on the rear side of the mirror at distance f.

h(image)/h(object)= -(v/u)= (18/9)=2. This is magnification .

So, h(image)=2x h(object)=(2)(3)= 6cm