English, asked by nagarathnanaik086, 4 months ago

a 3 cm tall object is placed perpendicular to principal axis of focal length of 15cm. the distance of the object from the lens is 30cm. find nature , position and size of the object

Answers

Answered by chemistrywala

0

Explanation:

u = -30cm

f= +-15cm

ho= 3cm

v= uf/u+f

CASE 1 :: TAKING CONVEX LENS

v== (-30)(15)/-30+15 = 30cm

image distance is 30 cm

image is real

CASE 2:: TAKING CONCAVE LENS

v= (-30)(-15)/-45 = -10 cm

image distance is 10 cm

image is virtual

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