Math, asked by ryannap10, 10 months ago

In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and HI = 69 feet. Find the length of IJ to the nearest tenth of a foot.
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Answers

Answered by av1266108

1

Answer:

The length of IJ is 68.7 feet.

Step-by-step explanation:

According to trigonometric identities for a right angled triangle, the sin of an angle is:

From the provided data we can interpret that:

Perpendicular = x feet

Hypotenuse = 69 feet

θ = 84°

Compute the value of x as follows:

Thus, the length of IJ is 68.7 feet.

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