A 3 cm tall object is placed perpendicular to the principal axis of a convex lens a focal length 30 cm. the distance of the object from the lens is 20 cm. use lens formula to find the position, size and nature of the image formed. [v=-60, h’=9]
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Given :
• Object Height (Ho) = 3 cm
• Object Position (u) = - 20 cm
• Focal length (f) = 30 cm
• Convex Lens
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To Find :
• Image Position , size and nature
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Solution :
Use lens formula
⇒1/f = 1/v - 1/u
⇒ 1/v = 1/f + 1/u
⇒ 1/v = 1/(30) + 1/(-20)
⇒ 1/v = 1/30 - 1/20
⇒ 1/v = (2 - 3)/60
⇒ 1/v = -1/60
⇒ v = - 60 cm
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⇒m = v/u = H'/Ho
⇒-60/-20 = H'/3
⇒3 = H'/3
⇒H' = 3 * 3
⇒ H' = 9 cm
Answered by
2
Answer:
9cm
Explanation:
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