Question

a=3 d=10 an=20

find n and sn​

Answer 1

Answer:

n=2.7

Step-by-step explanation:

by an formula you can solve

an= a+(n-1)d

n=2.7

Answer 2

Step-by-step explanation:

an=a+(n-1)d

an=a+(n-1)d20 =3+(n-1)10

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)10

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-3

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-32=3n-3

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-32=3n-32+3=3n

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-32=3n-32+3=3n5=3n

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-32=3n-32+3=3n5=3nn=5/3

an=a+(n-1)d20 =3+(n-1)1020=( 3n-3)1020/10=3n-32=3n-32+3=3n5=3nn=5/3n=1.67ans