a =3 d=101 Then For A.P Sn
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Sₙ = 101n²/2 - 95n/2 if a =3 d=101 Then For A.P Sn
Step-by-step explanation:
nth term = a + (n-1)d
Sum of n terms = (n/2)(First Term + Last term)
=> Sum of n terms =(n/2)(a + a + (n-1)d)
a = 3
d = 102
=> Sum of n terms =(n/2)( 3 + 3 + (n-1)101)
=> Sum of n terms = (n/2)(6+ (n-1)101)
=> Sum of n terms = (n/2)(101n - 95)
=> Sum of n terms = 101n²/2 - 95n/2
=> Sum of n terms = (101n² - 95n)/2
=> Sₙ = 101n²/2 - 95n/2
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