A 3-digit number 4A3 is added to another 3-digit number 984 to give four digit number
13B7, which is divisible by 11. Find (A+B).
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Answer:
4A3+984=13B7
1397 is divisible by 11
so,
B=9
1397-984=413
413=4A3
than
A=1
A+B=1+9=10
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