Question

A 3 kg block has dimensions as shown below. Calculate the pressure exerted by the box on the surface. ( Take g = 9.8 m s¯² )​

Answer 1

Answer:

Thrust (F)=Weightoftheblock=mg

=2kg×9.8=19.6N

Area of the table top (A)=length×breadth

=20cm×10cm

=

100

20

m×

100

10

m=0.02m

2

∴P=

A

F

=

0.02m

2

19.6N

=

2

1960

N/m

2

.

=980Pa(Since1Pa=1N/m

2

).

Explanation:

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