Question

A 3 meter long wire with area of cross section 6.25×10-5m2 found to stretch 0.3 m under a load of 1200kg.what is young's modules of wire.​

Answer 1

The Young modulus (Y) of the material is 1.920 × 10⁹ Pa

Given:

Area of cross-section (A) = 6.25 × 10⁻⁵ m²

Length of wire (l) = 3 cm = 3 × 10⁻² m

Change in length (Δ l) = 3 mm = 3 × 10⁻³ m

Mass of load (M) = 1200 Kg

Explanation:

From the formula we know,

Here,

F Denotes Force.

A Denotes Area

l Denotes length

Δ l Denotes Extension.

Remember, In this case the force will be caused by the weight of the body.

i.e. F = M g.

Substituting the values,

∴ The Young modulus (Y) of the material is 1.920 × 10⁹ Pa.

Answer 2

Answer:

meter long wire with area of cross section 6.25×10-5m2 found to stretch 0.3 m under a load of 1200kg.what is young's modules of wire.