Question

If (ac+bd) / (ac-bd) = (a²+b²) / (a²-b²)
Then Prove that a:b = c:d
Please give the answer. If you spam, I will report all your answers.

Answer 1

Answer:

ac + bd

Simplify ———————

ac - bd

Equation at the end of step

1

:

((a2)+(b2)) (ac+bd)

———————————-——————— = 0

((a2)-(b2)) ac-bd

STEP

2

:

a2 + b2

Simplify ———————

a2 - b2

Trying to factor as a Difference of Squares:

2.1 Factoring: a2 - b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : a2 is the square of a1

Check : b2 is the square of b1

Factorization is : (a + b) • (a - b)

Equation at the end of step

2

:

(a2 + b2) (ac + bd)

————————————————— - ————————— = 0

(a + b) • (a - b) ac - bd

STEP

3

:

Calculating the Least Common Multiple :

3.1 Find the Least Common Multiple

The left denominator is : (a+b) • (a-b)

The right denominator is : ac-bd