Physics, asked by mwrs9620, 1 year ago

a 3-phase induction motor is running at 2% slip. if the input to rotor is 1000 w, then mechanical power developed by the motor is

Answers

Answered by santy2
11

The formula is given by :

Mechanical power = (1 - S) × Power input.

Power input = 1000 W

S = 2%

S = 2/100 = 0.02

Doing the substitution we have :

(1 - 0.02) = 0.98

= 0.98 × 1000 = 980W

Answer :

= 980 W

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