a 3 wide path runs outside and around a rectraingle park of lenght 125m and breadth 65m . find the area of path
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Length of park = 125 m
Width of park = 65 m
Area of park = 125 * 65
= 8125 m^2
Length of Outer rectangle = 125+6
= 131 m
Width of outer rectangle = 65 + 6
= 71
Area of outer rectangle = 71 * 131
= 9301 m^2
Area of path = 9301 - 8125
= 1176 m^2
Width of park = 65 m
Area of park = 125 * 65
= 8125 m^2
Length of Outer rectangle = 125+6
= 131 m
Width of outer rectangle = 65 + 6
= 71
Area of outer rectangle = 71 * 131
= 9301 m^2
Area of path = 9301 - 8125
= 1176 m^2
Answered by
1
hii!!
here's ur answer...
given the Length of the rectangular park is 125m and breadth is 65m.
area of the rectangular park = l×b
= 125×65
= 8125m²
if the 3m wide path runs outside the park, then the length of the path will be = 125+3+3
= 125+6
= 131m
breadth of the path will be = 65+3+3
= 65+6
= 71m
therefore area of the park along with the path = l×b
= 131×71
= 9301m²
hence area of the path = 9301-8125
= 1176m²
hope this helps..!
here's ur answer...
given the Length of the rectangular park is 125m and breadth is 65m.
area of the rectangular park = l×b
= 125×65
= 8125m²
if the 3m wide path runs outside the park, then the length of the path will be = 125+3+3
= 125+6
= 131m
breadth of the path will be = 65+3+3
= 65+6
= 71m
therefore area of the park along with the path = l×b
= 131×71
= 9301m²
hence area of the path = 9301-8125
= 1176m²
hope this helps..!
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