Question

A 3000 kg truck moving at speed of 90m/s stops after covering some distance the force applied by break 27000 N compute the distance covered and work done by this force ?

Answer 1

Given,
Mass of truck, m=3000 kg
Initial velocity, u=90 m/s
Final velocity, v=0
Force, F=27000 N
Using F=ma
or a=F/m=27000 / 3000=9 m/s2
Again using equation,
v2−u2=2as
(0)2−(90)2=2×(−9)×s
s=450 m
Hence, the distance covered is 450 m.Work done,
W=F x s=27000 × 450=12150 kj

Answer 2

go to internet  and search about this