Question

A 3000 kg truck moving at the speed of 90m/s stops after some distance.The force applied by the breaks are 27000N.Compute the distance covered and the work done by this force.

Answer 1

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Answer 2

The distance covered and the work done by this force- 450m

Explanation:

a = -27000/3000

   = -9 m/s^2

speed, u = 90m/s

           v = 0 m/s

Using,

v^2 - u^2 = 2as

s = - 90 × 90 / 2 × -9

s = 450 m.

Note:  The negative sign under force, and acceleration  indicates that they are in a direction opposite to motion.